Questions
If two charges +q and +9q are separated by a distance 'd' and a point charge Q is placed on the line joining the above two charges and in between them such that all charges are in equilibrium. Then the charge Q and it's position are
detailed solution
Correct option is C
x=d9qq+1=d4 from qF1=F214π∈0Qqx2=14π∈09q2d2∴x=d4⇒q=−16Q9Talk to our academic expert!
Similar Questions
Infinite charges of magnitude q each are lying at x =1, 2, 4, 8... meter on X-axis. The value of intensity of electric field at point x = 0 due to these charges will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
