If two tuning forks A and B are sounded together, they produce 4 beats per second. A is then slightly loaded with wax, they produce 2 beats when sounded again. The frequency of A is 256. The frequency of B will be
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a
250
b
252
c
260
d
262
answer is B.
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Detailed Solution
nA = Known frequency = 256 Hz, nB = ?x = 4 bps, which is decreasing after loading (i.e. x↓) also known tuning fork is loaded so nA↓Hence nA↓ – nB = x↓ ... (i) → Correct nB – nA↓ = x↓ ... (ii) → Wrong⇒ nB = nA – x = 256 – 4 = 252 Hz.