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If for two vector $\vec{A} and \vec{B}, sum (\vec{A} + \vec{B})$ is perpendicular to the difference $(\vec{A} - \vec{B})$ . The ratio of their magnitude is

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Correct option is A

(A→+B→) is perpendicular to (A→−B→) . Thus (A→+B→)⋅(A→−B→)=0 or A2+B→⋅A→−A→⋅B→−B2=0Because of commutative property of dot product A→⋅B→=B→⋅A→∴ A2−B2=0 or A=BThus the ratio of magnitudes A/B=1

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If for two vector A→ and B→, sum (A→+B→) is perpendicular to the difference (A→−B→). The ratio of their magnitude is

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Ready to Test Your Skills?

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If for two vector $\vec{A} and \vec{B}, sum (\vec{A} + \vec{B})$ is perpendicular to the difference $(\vec{A} - \vec{B})$ . The ratio of their magnitude is