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If two waves of same frequency and same amplitude respectively, on superimposition produced a resultant disturbance of the same amplitude, the waves differ in phase by

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a
π
b
2π/3
c
π/2
d
Zero

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detailed solution

Correct option is B

A2=a2=a2+a2+2a2cosθ⇒cosθ=−12⇒θ=2π3


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Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is ‘a’ and the phase of A is ahead by π3 than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter 


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