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If $_{92} U^{238}$ undergoes successively 8 $α$ -decays and 6 $β$ -decays, then resulting nucleus is

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detailed solution

Correct option is B

z=92UA=238→ −1β0z'XA'So A'=A-4nα=238-4 x 8=206 and Z'=nβ-2nα+z=6-2 x 8+92 =82.

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If 92U238 undergoes successively 8 α-decays and 6 β-decays, then resulting nucleus is

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If $_{92} U^{238}$ undergoes successively 8 $α$ -decays and 6 $β$ -decays, then resulting nucleus is