If the unit of force is 2N, that of length is 4m and that of velocity is 6 ms−1, then the unit of linear momentum is

P α FaLbVcMLT−1=K[MLT−2]aLb[LT−1]cMLT−1=MaLa+b+cT−2a−ca =1   a+b+c =1  -2a-c =-1c=−1by solving above equations,a=1, b=1, c=-1b=1P=FLV=2 Newton4met6 met sec-1=43Kg met sec-2 metmet sec-1=43kg met sec-1