Questions
If the unit of force is 2N, that of length is 4m and that of velocity is
a
29 kg ms−1
b
43 kg ms−1
c
92 kg ms−1
d
25 kg ms−1
detailed solution
Correct option is B
P α FaLbVcMLT−1=K[MLT−2]aLb[LT−1]cMLT−1=MaLa+b+cT−2a−ca =1 a+b+c =1 -2a-c =-1c=−1by solving above equations,a=1, b=1, c=-1b=1P=FLV=2 Newton4met6 met sec-1=43Kg met sec-2 metmet sec-1=43kg met sec-1Talk to our academic expert!
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The quantities A and B are related by the relation A/B = m, where m is the linear mass density and A is the force, the dimensions of B will be
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