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$If unit vectors \hat{A} and \hat{B} are inclined at angle θ, then | \hat{A} - \hat{B} | is$

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2sinθ2

2cosθ2

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tanθ

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detailed solution

Correct option is A

|A^−B^|2 = A^−B^.A^−B^ = A^.A^ −A^.B^−B^.A^+B^.B^ = 1−A^.B^−A^.B^+1 = 2-2cosθ =2(1-cosθ) = 2(2sin2θ2) = 4sin2θ2A^−B^=2sinθ2

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If unit vectors A^ and B^ are inclined at angle θ, then |A^ −B^| is

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$If unit vectors \hat{A} and \hat{B} are inclined at angle θ, then | \hat{A} - \hat{B} | is$