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Q.

If  unit  vectors  A^  and  B^  are inclined  at  angle  θ,  then  |A^ −B^|  is

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a

2sinθ2

b

2cosθ2

c

2tanθ2

d

tanθ

answer is A.

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Detailed Solution

|A^−B^|2 = A^−B^.A^−B^                 = A^.A^ −A^.B^−B^.A^+B^.B^                = 1−A^.B^−A^.B^+1                = 2-2cosθ =2(1-cosθ)                  = 2(2sin2θ2)    = 4sin2θ2A^−B^=2sinθ2
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