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If the unit of velocity is run, the unit of time is second and unit of force is strength in a hypothetical system of unit. In this system of unit, the unit of mass is ${(strength)}^{x}$ ${(second)}^{y}$ ${(run)}^{z}$ . Find the value of $\frac{y}{x}$

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detailed solution

Correct option is D

F = ma⇒ m = Fa= ForceChange in velocityTime= Force ×TimeChange in velocity= (strength)(s)(run)-1Thus, x = 1, y = 1 and z = -1∴ yx = 1

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If the unit of velocity is run, the unit of time is second and unit of force is strength in a hypothetical system of unit. In this system of unit, the unit of mass is (strength)x(second)y(run)z. Find the value of yx

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If the unit of velocity is run, the unit of time is second and unit of force is strength in a hypothetical system of unit. In this system of unit, the unit of mass is ${(strength)}^{x}$ ${(second)}^{y}$ ${(run)}^{z}$ . Find the value of $\frac{y}{x}$