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If A = 5 units, B = 6 units and $| \vec{A} \times \vec{B} | = 15 units,$ then what is the angle between $\vec{A} and \vec{B}$ ?

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detailed solution

Correct option is A

sinθ = |A→ ×B→|AB = 155×6 = 12 ⇒ θ = 300

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If A = 5 units, B = 6 units and |A→ ×B→| = 15 units, then what is the angle between A→ and B→?

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Ready to Test Your Skills?

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If A = 5 units, B = 6 units and $| \vec{A} \times \vec{B} | = 15 units,$ then what is the angle between $\vec{A} and \vec{B}$ ?