First slide

Vectors

Question

If A = 5 units, B = 6 units and $| \vec{A} \times \vec{B} | = 15 units,$ then what is the angle between $\vec{A} and \vec{B}$ ?

Moderate

A

$30^{0}$
B

$60^{0}$
C

$90^{0}$
D

$120^{0}$

Solution

$sinθ = \frac{| \vec{A} \times \vec{B} |}{AB} = \frac{15}{5 \times 6} = \frac{1}{2} \Rightarrow θ = 30^{0}$

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