First slide

Scalars and Vectors

Question

If A = 5 units, B = 6 units and $| \vec{A} \times \vec{B} | = 15$ units, then what is the angle between $\vec{A} and \vec{B} ?$

Easy

A

30⁰
B

60⁰
C

90⁰
D

120⁰

Solution

$\sin θ = \frac{| \vec{A} \times \vec{B} |}{A B} = \frac{15}{5 \times 6} = \frac{1}{2} \Rightarrow θ = 30^{\circ}$

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