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If A = 5 units, B = 6 units and $| \vec{A} \times \vec{B} | = 15$ units, then what is the angle between $\vec{A} and \vec{B} ?$

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detailed solution

Correct option is A

sin⁡θ=|A→×B→|AB=155×6=12⇒θ=30∘

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If A = 5 units, B = 6 units and |A→×B→|=15 units, then what is the angle between A→ and B→?

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Ready to Test Your Skills?

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If A = 5 units, B = 6 units and $| \vec{A} \times \vec{B} | = 15$ units, then what is the angle between $\vec{A} and \vec{B} ?$