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Q.

If 10000 V is applied across an X-ray tube, what will be the ratio of de Broglie wave length of the incident electrons to the shortest wavelength of X-ray produced ( em for electron is 1.8×1011Ckg−1)

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a

1

b

0.1

c

0.2

d

0.3

answer is B.

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Detailed Solution

For the incident electron, 12mv2=eV or P=2mK=2meV∴ de Broglie wavelength, λ1=hp=h2meV Shortest X -ray wavelength λ2=hceV∴λ1λ2=1cV2em=1042×1.8×10113×108=0.1

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