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If $v = \sqrt{(5 gl)}$ , what will be the velocity of the bob at the top of vertical circle

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(gl/2)

(gl)

(2gl)

4gl

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detailed solution

Correct option is B

v2=u2+2ghHere u=(5gl),g=−g and h=2l∴ V2=5gl−4gl=gl or V=(gl)

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If v=(5gl), what will be the velocity of the bob at the top of vertical circle

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If $v = \sqrt{(5 gl)}$ , what will be the velocity of the bob at the top of vertical circle