If 120 V, 60 Hz AC voltage is applied to a circuit that consists of a 10 Ω resistor and a 20 H coil in series, then calculate the approximate value of current flowing in the circuit.

Given to us : Resistance =10ΩInductance = 20 HVoltage = 120 VFrequency = 60 HzAngular frequency =ω=2πf=2π(60)ω=120πFor the given circuit we can calculate the inductive capacitance as:XL=ωL=2π×60×20 =2400 π Ω As, XL>>R⇒Z=XLI=VZ≃120π2400π=0.016A