First slide

Stationary waves

Question

If v is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency n

Easy

A

$\frac{v}{4 n}$
B

$\frac{v}{2 n}$
C

$\frac{2 n}{v}$
D

$\frac{4 n}{v}$

Solution

For shortest length of pipe mode of vibration must be fundamental i.e., $n = \frac{v}{4 l} \Rightarrow l = \frac{v}{4 n} .$

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