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If v is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency n 

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a
v4n
b
v2n
c
2nv
d
4nv

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detailed solution

Correct option is A

For shortest length of pipe mode of vibration must be fundamental i.e., n=v4l⇒l=v4n.


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Two adjacent natural frequencies of an organ pipe are formed to be 550 Hz and 650 Hz. Calculate the length of this pipe (in m). (Velocity of sound in air 350 m/s).


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