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# If V is the volume of the vessel and ${V}_{L}$  is volume of liquid to be taken for the free space volume to be constant at all temperatures then

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a
VγR=VLγg
b
VLγg=VγR
c
VLγR=Vγg
d
Vγg=VLγR
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detailed solution

Correct option is D

change in volume of glass = change in volume of liquid ΔVg=ΔVL---(1) in terms of coefficient of volume expansion of glass γg and   coefficient of real expansion of liquid γR ; Δt change in temperature ; from γ=ΔVVΔt we get, from eqn(1) VγgΔt=VLγRΔt Vγg=VLγR

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A glass vessel is partially filled with mercury and when both are heated together, the volume of the unfilled part of vessel remains constant at all temperature. Find the initial volume (in cm3) of mercury if the empty part measures 34 cm3 ${\mathrm{\gamma }}_{\mathrm{Hg}}=18×{10}^{-5}{/}^{\circ }\mathrm{C}]$

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