Q.
If vectors A →= cosωt i^+sinωtj^ and B→ = cosωt2i^+sinωt2j^ are functions of time, then the value of t at which they are orthogonal to each other is:
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a
t = 0
b
t = π4ω
c
t = π2ω
d
t = πω
answer is D.
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Detailed Solution
A→ = cosωti^+sinωt j^B→ = cos(ωt2)i^+sinωt2 j^For A→ and B→ orthogonal A.→B→ = 0cosωt i^+sinωt j^.cosωt2i^+sinωt2j^ = 0cosωt.cosωt2+sinωt.sinωt2 = 0cos(ωt-ωt2) =0⇒ cosωt2 = 0ωt2 = π2 ⇒ ωt = π ⇒ t = πω
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