First slide
Instantaneous velocity
Question

If the velocity of a particle is v = At + Bt2, where A and B constants, then the distance travelled by it between 1s and 2s is.

Moderate
Solution

V = At + Bt2
ds/dt = At + Bt2 Integrating both sides weget
 

\int {ds = \int\limits_1^2 {(At + Bt^2 )} dt}


 

s = \left[ {\frac{{At^2 }} {2} + \frac{{Bt^3 }} {3}} \right]_1^2 = \frac{{4A}} {2} + \frac{{8B}} {3} - \frac{A} {2} - \frac{B} {3} = 3\frac{A} {2} + \frac{{7B}} {3}

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App