If the velocity of a particle is v = At + Bt2, where A and B are constants, then the distance travelled by it between Is and 2s is [NEET 2016]
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a
3A + 7B
b
32A + 73B
c
A2+B3
d
32A+4B
answer is B.
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Detailed Solution
Velocity of the particle is given as v = At + Bt2where, A and B are constants.⇒ dxdt=At+Bt2 ∵v=dxdt⇒ dx=At+Bt2dtIntegrating both sides, we get ∫x1x2dx=∫12At+Bt2dt⇒ Δx=x2-x1=A∫12tdt+B∫12t2dt =At2212+Bt3312 =A222-12+B323-13∴ Distance travelled by the particle between Is and 2s is Δx=A2×(3)+B3(7)=3A2+7B3