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Questions  

If the velocity of a particle is v=At+Bt2, where A and B are constants, then the distance travelled by it between 1s and 2s is

a
32A+73B
b
A2+B3
c
32A+4B
d
3 A+7 B

detailed solution

Correct option is A

Velocity of the particle is v=At+Bt2dsdt=At+Bt2,∫ds=∫At+Bt2dt∴s=At22+Bt33+Cs(t=1s)=A2+B3+Cs(t=2s)=2A+83B+C Required distance =s(t=2 s)-s(t=1 s)=2A+83B+C-A2+B3+C=32A+73B

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