Q.
If velocity v, acceleration A and force F are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of v, A and F would be
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a
FA−1v
b
Fv3A−2
c
Fv2A−1
d
F2v2A−1
answer is B.
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Detailed Solution
L ∝ vxAyFe ⇒ L = kvxAyFePutting the dimensions in the above relationML2T−1 = kLT−1xLT−2yMLT−2z⇒ML2T−1 = kMzLx+y+zT−x−2y−2zComparing the powers of M, L and TZ = 1X+y+z = 2-x-2y-2z = -1On solving (i), (ii) and (iii) x = 3, y = -2, z =1So dimension of L in terms of v, A and f[L] = [Fv3A−2]
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