If velocity v, acceleration A and force F are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of v, A and F would be

Question

Infinity Learn · Accepted Answer

L ∝ vxAyFe   ⇒ L $$=$$ kvxAyFePutting the dimensions in the above $$relationML2T$$−$$1$$ $$=$$ kLT−$$1xLT$$−$$2yMLT$$−$$2z$$⇒$$ML2T$$−$$1$$ $$=$$ $$kMzLx+y+zT$$−x−$$2y$$−$$2zComparing$$ the powers of M, L and TZ $$=$$ $$1X+y+z$$ $$=$$ $$2-x-2y-2z$$ $$=$$ $$-1On$$ solving (i), (ii) and (iii) x $$=$$ $$3$$, y $$=$$ $$-2$$, z $$=1So$$ dimension of L in terms of v, A and f[L] $$=$$ [$$Fv3A$$−$$2$$]

If velocity v, acceleration A and force F are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of v, A and F would be

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