Questions
If the velocity (V), acceleration (A), and force (F) are taken as fundamental quantities instead of mass (M) length (L), and time (T), the dimensions of Young's modulus (Y) would be
detailed solution
Correct option is A
Let Y=VaAbFc ML−1T−2=LT−1aLT−2bMLT−2c ML−1T−2=McLa+b+cT−a−2b−2c∴ c=1,a+b+c=−1,−a−2b−2c=−2 On solving, we get a=−4,b=2, and c=1.Talk to our academic expert!
Similar Questions
The quantities A and B are related by the relation A/B = m, where m is the linear mass density and A is the force, the dimensions of B will be
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