If the velocity v of a particle moving along a straight line decreases linearly with its displacement s from $$20$$ $$m/s$$ to a value approaching zero at s $$=$$ $$30$$ m figure, then acceleration of the particle at s $$=$$ $$15$$ m is

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Infinity Learn · Accepted Answer

The slope of the line $$=$$ $$-$$ $$2/3The$$ equation of line is given $$by(v$$â$$20)=$$â$$23(s$$â$$0)$$â´$$v=20$$â(2/3)sThe$$ velocity at s $$=$$ $$15$$ m is given $$byV=dsdts=15m=20$$â$$23$$Ã$$15=10m/sThe$$ acceleration can be obtained by differentiating eq. $$(1) with respect to time, i.e.,$$a=dvdt=0$$â$$23dsdt$$â´$$dvdts=15m=$$â$$23dsdts=15m=$$â$$23$$Ã$$10=$$â$$203m/s2$$

If the velocity v of a particle moving along a straight line decreases linearly with its displacement s from 20 m/s to a value approaching zero at s = 30 m figure, then acceleration of the particle at s = 15 m is

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