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Q.

If the velocity v of a particle moving along a straight line decreases linearly with its displacement S from 20 m/s to a value approaching zero at  S=30 m. Then acceleration of the particle at S=15 m is.

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a

23m/s2

b

−23m/s2

c

203m/s2

d

−203m/s2

answer is D.

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Detailed Solution

slope of graph=-23 from graph v=-23(s) +20---1 diff v w.r.t to time   dvdt=-23(dsdt) +d20dt a=-23(v) =-2(-2 3 s+20)3 fom (1) for s=15m: a=49(15) -403 =-203
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