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If the velocity v of a particle moving along a straight line decreases linearly with its displacement S from 20 m/s to a value approaching zero at  S=30m. Then acceleration of the particle at S=15m is.

a
23m/s2
b
−23m/s2
c
203m/s2
d
−203m/s2

detailed solution

Correct option is D

slope of graph=-23 from graph v=-23(s) +20---1 diff v w.r.t to time   dvdt=-23(dsdt) +d20dt a=-23(v) =-2(-2 3 s+20)3 fom (1) for s=15m: a=49(15) -403 =-203

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