If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength (λmin) of at X-ray continuous spectrum shifts by Δλ = 26 pm. The initial voltage applied to the tube is

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≈ 10 kV

≈ 16 kV

≈ 50 kV

≈ 75 kV

answer is B.

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Detailed Solution

λmin=hceV⇒λ1hceV1 and λ2=hceV2∴Δλ=λ2−λ1=hce1V2−1V1.Given V2=1.5V1on solving we get V1=16000 volt =16kV.

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