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If the volume of a gas is doubled at constant pressure, the average translational kinetic energy of its molecules will
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Correct option is A
At constant pressure,V1T1=V2T2⇒T2=V2V1×T1=2T1Average translational kinetic energy . =12mvRMS2 =32RTmMα temperatureSince, temperature doubles, average translational KE of molecules also doubles.Similar Questions
Two identical containers A and B have frictionless pistons. They contain the same volume of an ideal gas at the same temperature. The mass of the gas in A is mA and that in B is mB. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The change in the pressure in A and B, respectively, is p and 1.5 p. Then
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