Q.

If the volume of a gas is doubled at constant pressure, the average translational  kinetic energy of its molecules will

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a

be doubled

b

be halved

c

remain the same

d

become 4 times

answer is A.

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Detailed Solution

At constant pressure,V1T1=V2T2⇒T2=V2V1×T1=2T1Average translational kinetic energy . =12mvRMS2 =32RTmMα temperatureSince, temperature doubles, average translational KE of molecules also doubles.
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