Q.
If the volume of a gas is doubled at constant pressure, the average translational kinetic energy of its molecules will
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a
be doubled
b
be halved
c
remain the same
d
become 4 times
answer is A.
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Detailed Solution
At constant pressure,V1T1=V2T2⇒T2=V2V1×T1=2T1Average translational kinetic energy . =12mvRMS2 =32RTmMα temperatureSince, temperature doubles, average translational KE of molecules also doubles.
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