If the water falls from a dam into a turbine wheel 19.6 m below, then the velocity of water (in m/s) at the turbine is (g=9.8 m/s2)

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answer is 19.6.

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Detailed Solution

Potential energy of water = kinetic energy at turbine mgh=12mv2⇒v=2gh=2×9.8×19.6=19.6 m/s

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