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If the wavelength of the first line of the Balmer series of hydrogen is $6561 \overset{0}{A}$ , find the wavelength of the second line of the series.

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13122A0

3280A0

4860A0

2187A0

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detailed solution

Correct option is C

The wavelength of spectral line in Balmer series is given by 1λ=R[122−1n2] For first line of Balmer series, n=3⇒1λ1=R[122−132]=5R36 For second line n=4⇒1λ2=R[122−142]=3R16∴λ2λ1=2027⇒λ2=2027×6561=4860Å

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If the wavelength of the first line of the Balmer series of hydrogen is 6561A0, find the wavelength of the second line of the series.

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Ready to Test Your Skills?

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If the wavelength of the first line of the Balmer series of hydrogen is $6561 \overset{0}{A}$ , find the wavelength of the second line of the series.