Questions
If the wavelength of the first line of the Balmer series in the hydrogen spectrum is
detailed solution
Correct option is B
For first line of Balmer series1λ=R(122−132)⇒R=365λ∴ wavelength of the first line, λL of the Lyman series is given by1λL=R(1−122)=365λ×34=275λ⇒λL=5λ27Talk to our academic expert!
Similar Questions
Determine the separation of the first line of the Balmer series (in ) in a spectrum of ordinary hydrogen and tritium (mass number 3). Take Rydberg's constants = 10967800 m-1.
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