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Questions  

If the wavelength of the first line of the Balmer series in the hydrogen spectrum is λ , then the wavelength of the first line of the Lyman series is

a
(27/5)λ
b
(5/27)λ
c
(32/27)λ
d
(27/32)λ

detailed solution

Correct option is B

For first line of Balmer series1λ=R(122−132)⇒R=365λ∴ wavelength of the first line, λL of the Lyman series is given by1λL=R(1−122)=365λ×34=275λ⇒λL=5λ27

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