Questions
If the wavelength of the incident radiation changes from , then the maximum kinetic energy of the emitted photo electrons changes from ,then the work function of the emitter surface is
detailed solution
Correct option is A
hcλ1 = W+K1dividing bothhcλ2 = W+K2λ2λ1 = w+k1w+k2λ2w+λ2k2 = λ1w+λ1w+λ1k1λ2k2−λ1k1 = wλ1−λ2w = λ2k2−λ1k1λ1−λ2 = λ1k1−λ2k2λ2−λ1Talk to our academic expert!
Similar Questions
Light described at a place by equation falls on metal surface having work function 2 eV, the maximum kinetic energy of photoelectrons?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests