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If wavelength of photon emitted due to transition of an electron from the third orbit to the first orbit in a hydrogen atom is λ then the wavelength of photon emitted due to transition of electron from the fourth orbit to the second orbit will be

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a

12827λ

b

259λ

c

367λ

d

12511λ

answer is A.

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Detailed Solution

1λ=R112−132 ⇒ λ=98R Again, 1λ′=R122−142⇒λ′=163R Now, λ′λ=163R×8R9 or λ′=12827λ

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