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Q.

If we assume that penetrating power of any radiation particle is inversely proportional to its de-Broglie wavelength of the particle then

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a

A proton and an alpha-particle after getting accelerated through same potential difference will have equal penetrating Power.

b

Penetrating power of alpha-particle will be greater than that of proton which have been accelerated by same potential difference.

c

Proton's penetrating power will be less than penetrating power of an electron which has been accelerated by the same potential difference.

d

Penetrating powers cannot be compared as all these are particles having no wavelength or wave nature.

answer is B.

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Detailed Solution

λ=hp=h2mE⇒h2mVq∴For  higher  m  and  q,λ  will  be  smaller.For  an  'α'  particle,   both  'm'   and   'q'  are  higher.Hence,   lesser   is  the   wavelength.As,  (Penetrating  power)∝Energy∝1λFrom  above , penetrating power of an "α" particle is more than that of a proton.
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If we assume that penetrating power of any radiation particle is inversely proportional to its de-Broglie wavelength of the particle then