Questions
If we assume that penetrating power of any radiation particle is inversely proportional to its de-Broglie wavelength of the particle then
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a
A proton and an alpha-particle after getting accelerated through same potential difference will have equal penetrating Power.
b
Penetrating power of alpha-particle will be greater than that of proton which have been accelerated by same potential difference.
c
Proton's penetrating power will be less than penetrating power of an electron which has been accelerated by the same potential difference.
d
Penetrating powers cannot be compared as all these are particles having no wavelength or wave nature.
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Correct option is B
λ=hp=h2mE⇒h2mVq∴For higher m and q,λ will be smaller.For an 'α' particle, both 'm' and 'q' are higher.Hence, lesser is the wavelength.As, (Penetrating power)∝Energy∝1λFrom above , penetrating power of an "α" particle is more than that of a proton.Similar Questions
According to Bohr's postulates, which of the following quantities takes discrete values
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