Questions
If we express the energy of a photon in KeV and the wavelength in angstroms, then energy of a photon can be calculated from the relation
a
E=12.4 hv
b
E=12.4 h/λ
c
E=12.4 /λ
d
E= hv
detailed solution
Correct option is C
Energy of photon E=hcλJoules=hceλeV⇒EeV=6.6×10−34×3×1081.6×10−19×λA0=12375λAo⇒EkeV=12.37λAo≈12.4λTalk to our academic expert!
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If a photon has velocity c and energy E, then which of following represents its wavelength?
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