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If a wire is stretched by hanging a weight from its end, the elastic potential energy per unit volume in terms of the longitudinal strain $σ$ and modulus of elasticity $Y$ is :

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Yσ2/2

Yσ/2

2Yσ2/2

Y2σ/2

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detailed solution

Correct option is A

U=12stream×strain =12 Y.(strain)2 =σ22Y

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If a wire is stretched by hanging a weight from its end, the elastic potential energy per unit volume in terms of the longitudinal strain σ and modulus of elasticity Y is :

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Ready to Test Your Skills?

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If a wire is stretched by hanging a weight from its end, the elastic potential energy per unit volume in terms of the longitudinal strain $σ$ and modulus of elasticity $Y$ is :