If the work done is stretching a wire by 1 mm is 2 J, the work necessary for stretching another wire of same material but double the radius of cross-section and half the length .
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a
14J
b
4 J
c
8 J
d
16 J
answer is D.
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Detailed Solution
W = 12F∆lW = 12×Yπr2∆ll∆l Y = Flπr2∆lor W = Yπr2∆l22l F = Yπr2∆llor W ∞ r2l, W' ∞ (2r)22lW'W = 8 or W' = 8×2 J = 16 J