Q.

If x and a stand for distance, then for what value of n is the given equation dimensionally correct? The equation is ∫dxa2−xn=sin−1⁡xa

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a

0

b

2

c

-2

d

1

answer is B.

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Detailed Solution

Here xn has the same dimensions as a2. Thus, n = 2 will make the expression dimensionally correct.
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If x and a stand for distance, then for what value of n is the given equation dimensionally correct? The equation is ∫dxa2−xn=sin−1⁡xa