If y $$=$$ ex . $$cot$$ x then dydx will be

Correct option is 3ex[cot x – cosec2x]

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If y = e^x . cot x then $\frac{d y}{d x}$ will be

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detailed solution

Correct option is C

y=ex⋅cot⁡xdydx=exddx(cot⁡x)+cot⁡xddxex=ex−cosec2⁡x+cot⁡xex=excotx−cosec2⁡x

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If y = ex . cot x then dydx will be

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If y = e^x . cot x then $\frac{d y}{d x}$ will be