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Questions  

 If y=2sin2θ+tanθ then dydθ will be 

a
4sin⁡θcos⁡θ+sec⁡θtan⁡θ
b
2sin⁡2θ+sec2⁡θ
c
4sin⁡θ+sec2⁡θ
d
2cos2⁡θ+sec2⁡θ

detailed solution

Correct option is B

y=2sin2⁡θ+tan⁡θy'=2×2sin⁡θcos⁡θ+sec2⁡θy'=2sin⁡2θ+sec2⁡θ

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