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Q.

If y = 3t2 – 4t ; then minima of y will be at :

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a

3/2

b

3/4

c

2/3

d

4/3

answer is C.

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Detailed Solution

y=3t2−4tdtdy=6t−4=0⇒t=2/3⋅d2ydt2=6>0 Hence there will be minima at t=2/3
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