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If y = 3t² – 4t ; then minima of y will be at :

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Correct option is C

y=3t2−4tdtdy=6t−4=0⇒t=2/3⋅d2ydt2=6>0 Hence there will be minima at t=2/3

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If y = 3t2 – 4t ; then minima of y will be at :

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If y = 3t² – 4t ; then minima of y will be at :