If y $$=$$ $$x2sin(x3)$$ then ∫y dx will be :

Correct option is 2−cos⁡x33+C

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If y = x²sin(x³) then $\int$ y dx will be :

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−cos⁡x3+C

−cos⁡x33+C

cos⁡x3+C

cos⁡x33+C

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detailed solution

Correct option is B

y=x2sin⁡x3∫x2sin⁡x3dx let u=x3⇒du=3x2dx∫sin⁡udu3=13(−cos⁡u)+C=−13cos⁡x3+C

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If y = x2sin(x3) then ∫y dx will be :

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

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If y = x²sin(x³) then $\int$ y dx will be :