If y=x2+3x+23+logex2. Then, find dydx.
(2x+3)x2+3x+22+2x
3(2x+3)x2+3x+22+2x
3(2x+3)x2+3x+23+2x
3(2x+3)x2+3x+22
Using the chain rule, we have
dydx=3x2+3x+23-1·(2x+3)+1x2·2x =3(2x+3)x2+3x+22+2x