If $$y=x2+2x1/2$$, then find dydx.

Correct option is 1(x+1)x2+2x-1/2

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If $y = \{{(x^{2} + 2 x)}^{1 / 2}\}$ , then find $\frac{d y}{d x} .$

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(x+1)x2+2x-1/2

(x+2)x2+2x-1/2

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(x+1)x2+2x2

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detailed solution

Correct option is A

Using the chain rule, we havedydx=12x2+2x12-1(2x+2) =(x+1)x2+2x-1/2

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If y=x2+2x1/2, then find dydx.

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If $y = \{{(x^{2} + 2 x)}^{1 / 2}\}$ , then find $\frac{d y}{d x} .$