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$If y = x^{3} + 2 x^{2} + 7 x + 8 then \frac{d y}{d x} will be$

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3x2+2x+15

3x2+4x+7

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Correct option is B

y=x3+2x2+7x+8 differentiate on both sides w.r.t ' x′dydx=ddxx3+2x2+7x+8=3x2+2(2a)+7(1)+0∵dcdx=0,dxdx=1,dxndx=nxn−1=3x2+4x+7

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If y=x3+2x2+7x+8 then dydx will be

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$If y = x^{3} + 2 x^{2} + 7 x + 8 then \frac{d y}{d x} will be$