First slide

The lens

Question

The image distance of an object placed 10 cm in front of a thin lens of focal length + 5 cm is

Moderate

A

$6 .5 cm$
B

$8 .0 c m$
C

$9 .5 cm$
D

$10 .0 cm$

Solution

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{+ 5} = \frac{1}{v} - \frac{1}{(- 10)} \Rightarrow v = 10 cm$

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