The image of an object placed on the principal axis of a concave mirror of focal length $$12$$ cm is formed at a point which is $$10$$ cm more distance from the mirror than the object. The magnification of the image is

Question

The image of an object placed on the principal axis of a concave mirror of focal length $$12$$ cm is formed at a point which is $$10$$ cm more distance from the mirror than the object. The magnification of the image is

Infinity Learn · Accepted Answer

$$1-x+1-x-10=-112$$ or          $$1x+1x+10=112$$ or          $$x+10+xxx+10=112$$ or         $$2x+10x2+10x=112$$ or         $$x2+10x=24x+120$$ or         $$x2-14x-120=0$$             $$x2-20x+6x-120=0$$ or        $$xx-20+6x-20=0$$            $$x+6x-20=0$$ Here  u $$=$$ $$-20$$ cm ν$$=-20+10cm=-30$$ cm then  magnification m $$=$$ $$-$$ $$vu=--30-20=-1.5$$

The image of an object placed on the principal axis of a concave mirror of focal length 12 cm is formed at a point which is 10 cm more distance from the mirror than the object. The magnification of the image is

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