Imagine earth to be a solid sphere of mass M and radius R. If the value of acceleration due to gravity at a depth 'd' below earth's surface is same as its value at a height 'h' above its surface and equal to g4 (where g is the value of acceleration due to gravity on the surface of earth), the ratio of hd will be:

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Detailed Solution

gd = gh=g4g1−dR = g1+hR2=g4Solving we get d=3R4, h=Rhd=R3R/4=43

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