Download the app

Questions  

Imagine a light planet revolving around a very massive star in a circular orbit of radius r with a period of revolution T. If the gravitational force of attraction between the planet and the star is proportional to r5/2, then the square of the time period will be proportional to

a
r3
b
r2
c
r2.5
d
r3.5

detailed solution

Correct option is D

mv2r=GMmr5/2∵F∝1r5/2or  rω2=GMr5/2or  r4π2T2=GMr5/2or  T2∝r7/2 or T2∝r3.5

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

In the following four periods     
(i) Time of revolution of a satellite just above the earth’s surface  (Tst)
(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth  (Tma)
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg  (Tsp)
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field  (Tis)
 


phone icon
whats app icon