Questions
Imagine a light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between the planet and the star is proportional to , then
detailed solution
Correct option is B
The gravitational force F ∝ 1R52 givenF=CR52−−−−−1here C is constantThe centripetal force for the planet =mRω2=mR2πT2−−−−−2Centripetal force is provided from gravitational force (1) = (2)F=CR52=mR2πT2⇒T2 ∝ R52R⇒T2 ∝ R72Therefore, the correct answer is (B)Talk to our academic expert!
Similar Questions
In the following four periods
(i) Time of revolution of a satellite just above the earth’s surface
(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field
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