Q.

At an incident radiation frequency of v1, which is greater than the threshold frequency, the stopping potential for a certain metal is V1. At frequency 2v1, the stopping potential is 3V1. If the stopping potential at frequency 4v1 is n V1, then n is ………

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answer is 7.

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Detailed Solution

According to Einstein's equation, hv=hv0+eV⇒ V=hev−v0Given V1=hev1−v0 and 3V1=he2v1−v0⇒ 3V1V1=2v1−v0v1−v0⇒v1=2v0∴ V1=he2v0−v0=hev0At frequency 4v1, nV1=he4v1−v0                                  =he8v0−v0=7×hev0⇒ nV1=7V1⇒n=7
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