An inclined plane of height h and length l have the angle of inclination θ. The time taken by a body to come from the top to the bottom of this inclined plane will be
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a
sinθ2hg
b
1sinθ2hg
c
2hg
d
2lg
answer is B.
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Detailed Solution
Force down the plane =mgsinθ ∴ Acceleration down the plane =gsinθUsing the relation, h=ut+12gt2l=0+12(gsinθ)t2⇒ t2=2lgsinθ=2hgsin2θ ∵l=hsinθt=1sinθ2hg