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Q.

An inclined plane making an angle of 300 with the horizontal is placed in a uniform horizontal electric field of 100 Vm . A particle of mass 1kg and charge 0.01C is allowed to slide down from rest from height of 1m. If the coefficient of friction is 0.2 ,  find the time taken by the particle to reach the bottom ( in seconds ) . Take  g=9.8 m/s2

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answer is 0001.34.

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Detailed Solution

electrostatic force, F=Eq N=Eq sin30o+mg cos300  = 8.99N  Acceleration down the plane  a=mg sin300−μN−Eq cos300m ⇒a = (1)(9.8) (12) - (0.2)(8.99) - (100)(0.01)(32) 1 ⇒a=2.236 m/s2  Displacement along the plane S=1sin300=2m  Using s=ut+12at2 ⇒2=122.236t2 ⇒42.236=t2 ⇒t=1.34 sec
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